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A circular plate of uniform thickness ha...

A circular plate of uniform thickness has a diameter of 56 cm. A circular portion of diameter 42 cm is removed 'from one edge of the plate as shown in figure. Find the position of the centre of mass of the remaining portion.

A

9 cm

B

9 cm rightward

C

9 cm leftwards

D

zero

Text Solution

Verified by Experts

The correct Answer is:
C
Suppose `r_1` be the distance of centre of mass of the remaining portion from centre of the bigger circle, then `A_1r_1=A_2r_2, r_1((A_2)/(A_1))r_2=(pi(42)^2)/(pi[(56)^2-(42)^2])xx7 =9 cm`
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