A uniform rod of length 1 m is bent at its midpoint to make `90^@` angle. Calculate the distance of the centre of mass from the centre of the rod.

Options

A. 15 cm
B. 17.7 cm
C. 18.5 cm
D. 20 cm

Answer

B

Explanation

`c_1` and `c_2` denote the centres of mass of OB and OA respectively.
`:. (c_1c_2)^2=(25)^2+(25)^2, :. c_1c_2=25 sqrt2=35.35cm`
`:.` Distance of effective centre of mass = `(35.35)/2 =17.7` cm
Distance (O to C.M.)=Distance (`c_1` to C.M.)=(C.M. to `c_2` )
`:.` Distance C.M. from centre of rod = 17.7.cm