Home
Class 11
PHYSICS
What will be the acceleration due to gra...

What will be the acceleration due to gravity on the surface of the moon if its radius were (1/4) th the radius of earth and its mass (1/80) th the mass of earth ? What will be the escape velocity on the surface of moon if it is 11.2 km / s on the surface of the earth ? G(iven that `g = 9 . 8 m//s^(-2)` )

Text Solution

Verified by Experts

As on the surface of planet `g = ((GM)/(R^(2)))`
`(g_(M))/( g_(g)) = (M_(M))/(M_(B)) xx ((R_(g))/(R_(m)))^(2) = (1)/(80) xx (4)^(2) = (1)/(5)`
`:. g_(M) = (g_(g))/( 5) = (9 . 8)/( 5) = 1. 96 m // s^(2)`
Furthermore as escape velocity `v_(e) = sqrt((2 GM // R))`
So, `(v_(M))/( v_(B)) = sqrt((M_(M))/(M_(B))xx (R_(E))/(R_(M))) = sqrt((1)/(80) xx 4) = (1)/(sqrt(20))`
i.e. `v_(M) = ((v_(E))/(sqrt(20))) = = ((11.2)/( 4 . 47)) = 2. 5 km //s`
Promotional Banner

Similar Questions

Explore conceptually related problems

The acceleration due to gravity (g) on the surface of the the earth is 9.8 m/s^2 . At what height 'h' will the value of 'g' be half of that on the surface of the earth?

The value of acceleration due to gravity is maximum on the surface of the earth. Obtain an equation for the variation of 'g' with height.

The value of acceleration due to gravity is maximum on the surface of the earth. Draw a graph showing the variation of 'g' with depth and height from the surface of the the earth. assume that the density of the Earth is constant.

The acceleration due to gravity (g) on the surface of the earth is 9.8 m/s^2 . Derive an expression an expression for the variation of g with height (h) above the surface of the earth.