The mass percentage in composition of dry air at sea level contains approximately 75.5% of nitrogen. If the atmospheric pressure is 1 atm, then what will be the partial pressure of Nitrogen.
(average molecular mass of air=29)

Explanation

The mole fraction of nitrogen `=(M_("Nitrogen"))/("molecular wt.")=(0.755xx29)/(28)=0.78`
The partial pressure of Nitrogen `=P_(1)=mu_(1) (RT)/(V) =(mu_(1))/(mu) (muRT)/(V) =((mu_(1))/(mu))P =0.78xx1=0.78` atm.