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Two monoatomic ideal gases A and B occup...

Two monoatomic ideal gases A and B occupying the same volume V are at the same temperature T and pressure p. If they are mixed, the resultant mixture has volume V and temperature T. The pressure of the mixture is

A

p

B

`(p)/(2)`

C

4p

D

2p

Text Solution

Verified by Experts

The correct Answer is:
D
`(P_(1)V_(1))/(T_(1))=(P_("mix") xx V_("mix"))/(T_("mix"))`
Here, `T_(1)=T_("mix")=T`
`V_(1)=V+V`
`V_("mix")=V`
`:. (P xx 2V)/(T)=(P_("mix") xx V)/(T)`
`rArr P_("mix")=2P`
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