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A dielectric is placed in between the tw...

A dielectric is placed in between the two parallel plates of a capacitor is shown in figure. The dielectric constant of the dielectric is K. If the initial capacitance is C, then the modified capacitance will be

A

KC

B

(K + 1)C

C

`((K + 1)C)/(2)`

D

(K - 1)C

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  • A dielectric slab is placed between the plates of a parallel plates capacitor. Its capacitance

    A
    becomes zero
    B
    remains the same
    C
    decreases
    D
    increases
  • A dielectric slab is placed between the plates of a parallel plate capacitor. Its capacitance

    A
    becomes zero
    B
    remains the same
    C
    decreases
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  • A dieletric slab is partially introduced between two square plates of area of a parallel plane capacitor as shown in figure. Dielectric constant of slab is epsilon_(r ) . Total capacitance of the system is

    A
    `(epsilon_(0)sqrt(Ax))/(d)`
    B
    `(epsilon_(0))/(d)(epsilon_(r)sqrt(Ax)-Asqrt(Ax))`
    C
    `(epsilon_(0))/(d)(A-sqrt(Ax)+epsilon_(r)sqrt(Ax))`
    D
    `(epsilon_(0)epsilon_(r))/(d)(-sqrt(Ax)+A+epsilon_(r)sqrt(Ax))`
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