Home
Class 12
PHYSICS
A potentiometer circuit has been set up ...

A potentiometer circuit has been set up for finding the internal resistance of a given cell. The main battery used across the potentiometer wire, has an emf of 2V and negligible internal resistance. The potentiometer itself is 4m long. When the resistance `'R_(1)'`, connected across the given cell has values of (i) infinity (ii) `9.5Omega`, the balancing length on the potentiometer wire are found to be 3m and 2.85m respectively. The value of internal resistance of the cell is

A

`0.25Omega`

B

`0.95Omega`

C

`0.5Omega`

D

`0.75Omega`

Text Solution

Verified by Experts

Promotional Banner

Similar Questions

Explore conceptually related problems

Using a potentiometer how do you determine the internal resistance of a cell?

With the help of a circuit diagram describe the method to find the internal resistance of a cell using potentiometer.

Potentiometer is used to determine the internal resistance of a cell using potentlometer:- A potentiometer is a device for ________.

A potentiometer wire of length 100 cm has resis tance of 10 ohms. It is connected in series with a resistance R and a cell of emf 2V and negligible in ternal resistance. The circuit is as shown below. - What is the principle of a potentiometer ?

A potentiometer wire of length 100 cm has resis tance of 10 ohms. It is connected in series with a resistance R and a cell of emf 2V and negligible in ternal resistance. The circuit is as shown below. - Why is it prefered over a voltmeter ?

A 50V battery is connected across 10 ohm resistor and a current of 4.5A flows. The internal resistance of the battery is