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The electric field part of an electromag...

The electric field part of an electromagnetic wave in a medium is represented by `E_(y)=2.5 NC^(-1) xx cos [(2pi xx 10^6 rads^(-1))t -(pi xx 10^(-2) "radm"^(-1)x)], E_(x)=0`. The wave is

A

moving along the x-direction with frequency `10^6Hz` and wavelength 100m

B

moving along x-direction with frequency `106Hz` and wavelength 200m

C

moving along-x-direction with frequency `10^6Hz` and wavelength 200m

D

moving along y-direction with frequency `2 xx 10^(6) Hz` and wavelength 200m.

Text Solution

Verified by Experts

The correct Answer is:
B
`E_(x)=0 , E_(y) =2.5N//C xx cos [2pi xx 10^(6) rad//s] t-(pi xx 10^(-2) rad//m)x], E_(z)=0`
This shows that the wave is propagating along x-axis
Comparing the given equation with
`E=E_(0) cos (omegat-kx) " we have "omega=2pi xx 10^6`
`2piv=2pi xx 10^6 , v=10^(6) Hz=(2pi)/(lambda)=k=pi xx 10^(-2), lambda=(2pi)/(pi xx 10^(-2))=200m`
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