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In a Neon discharge tube 2.9 xx 10^(18) ...

In a Neon discharge tube `2.9 xx 10^(18) Ne^(+)` ions move to the right each second, while `1.2 xx 10^(18)` electrons move to the left per second, electron charge is `1.6 xx10^(-19)C.` The current in the discharge tube is

A

1 A towards right

B

0.66 A towards right

C

0.66 A towards left

D

zero

Text Solution

Verified by Experts

The correct Answer is:
B
Charge on ions `= 2. 9 xx 10 ^(18) xx 1. 6 xx 10 ^(-19) C`
Charge on electrons `= 1.2 xx 10 ^(18) xx 1. 6 xx 10 ^(-19) C`
Total charge `= 4.1 xx 1.6 xx 10 ^(-1) C = 6.56 xx 10 ^(-1) C = 0.66 C.`
Current `= ("Charge")/("Time") = (0.66 (C))/(1 (s)) = 0.66 A`
The direction of current in a circuit is, by convention, taken along the direction in whcih positiv echarges flow. Hence the current in the ischarge tube flows towards right.
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