The radius of the hydrogen atom in its ground state is `5.3xx 10^(-4) m.` After collision with an electron it is found to have a radius of `21.2 xx 10^(-41) m.` The principal quantum number of final state of the atom is:

Options

A. 2
B. 3
C. 4
D. 16

Explanation

`(r _(2))/( r_(1)) = ((n _(2))/( n_(1)) ) ^(2) : (21.2 xx 10 ^(-11))/( 5. 3 xx 10 ^(-11)) = ((n _(2))/( 1)) ^(2),4=n _(2) ^(2) n _(2) = 2`