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The electron in a hydrogen atom makes a ...

The electron in a hydrogen atom makes a transition `n _(1) to n _(2)` where `n_(1) and n_(2)` are the principal quantum numbers of the two states. Assume the Bohr model to be valid. The frequency of orbital motion of the electron in the initial state is `(1)/(27)` of that in the final state. The possible values of `n_(1) and n_(2)` are

A

`n _(1) =4, n _(2) = 2`

B

`n _(2) = , n _(2) =1`

C

`n _(1) = 8, n _(2) =1`

D

`n_(1) = 6, n _(2) = 3`

Text Solution

Verified by Experts

`T alpha n ^(3)`
`(T_(i))/( T _(f) ) = (1)/( 27) = ((n _(i))/( n _(2))) ^(3) implies (n _(1) )/( n _(2)) = (1)/(3)`
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