An electron in hydrogen atom first jumps from `n^(th)` excited state to `(n - 1)^(th)` excited state and then from `(n - 1)^(th)` excited state to `(n-2)^(th)` excited state. If the ratio of energy of photons emitted in these two cases is `(5)/(27),` then find the ratio ofmomentums.

Options

A. `0.275`
B. `4.7`
C. `5.4`
D. `0.185`

Explanation

Ratio of energy of photons `= (5)/(27) = E`
`E alpha (1)/(lamda ) (E = (hc )/(lamda )) and p prop E ` (since, `p = (E)/(C))`
Ratio of momentums = `(5)/(27) = 0.185`