An energy of 24.6 eV is required to remove one of the electrons from the neutral helium atom. The energy (in electron volts) required to remove both the electrons from a neutral helium atom is

Options

A. `38.2`
B. `49.2`
C. `51.8`
D. `79.0`

Explanation

Energy required to remove one electron is
`E _(1) = 24.6 eV`
The energy required to remove the second electron is
`E _(2) = Z ^(2) Rhc ((1)/( 1 ^(2)) - (1)/((oo) ^(2)))= (2)^(2) xx 13.6 eV 54.4 eV`
Therefore , the total energy required is `E _(1) + E_(2) = 24.6 + 54.4 = 79.0 eV`