The helium gas in an excited state makes transition from excited state of principal quantum number n=5 to ground state. The most energetic photons have energy 52.224 eV, find the energy of least energetic photons.

Options

A. `1.224 eV`
B. `2.42 eV`
C. `3.22 eV`
D. `3.82 eV`

Explanation

Maximum energy is liberated when transition is from `n = 5` to `n =1` and minimum energy is liberated when transition is from `n =5` to `n =4.`
`( E _(1))/( 5 ^(2)) - E _(1) = 52.224 implies E _(1) = (- ) 54.4 eV`
and `(E _(1))/(5 ^(2)) - (E _(1))/( 4 ^(2)) = (9)/(400) E _(1) = (9)/(400) xx 54.4 eV = 1.22`