The length of germanium rod is 0.928 cm and its area of cross-section is `1 mm^2.` If for germanium `n_i= 2.5 xx 10^(19) m^(-3), mu_(h)=" 0.19 m"^2V^(-1)s^(-1), mu_(e)=0.39 m^2 V^(-1) s^(-1)`, find its resistance.

Options

A. `2.5k Omega`
B. `4.0 k Omega`
C. `5.0 k Omega`
D. `10.0 k Omega`

Answer

A

Explanation

We have `R=(pl)/A=(L)/(n_(i) e(mu_(e)+mu_(h))A)=(0.928 xx 10^(-2))/(2.5 xx 10^(19) xx 1.6 xx 10^(-19) (0.39+0.19) xx 10^(-6))=4000 Omega`