समान द्रव्यमान परन्तु विभिन्न घनत्व `rho_1" व "rho_2`, के दो द्रव मिलाये जाते हैं। मिश्रण का घनत्व `rho` होगा-

Options

A. `rho = (rho_(1)+rho_(2))/2`
B. `rho = (rho_(1)+rho_(2))/(2rho_(1)rho_(2))`
C. `rho= (2rho_(1)rho-(2))/(rho_(1)+rho_(2))`
D. `rho=(rho_(1)rho_(2))/(rho_(1)+rho_(2))`

Answer

C

Explanation

`rho = ("कुल द्रव्यमान")/(" कुल आयतन ")`
`(2m)/(V_(1)+V_(2)) =(2m)/(m(1/(p_(1))+1/(p_(2))))`
`rho = (2rho_(1)rho_(2))/(rho_(1)+rho_(2))`