संलग्न चित्र एक कार्नो चक्र को दर्शाता है जिसमे कार्नो इन्जन दो तापों `T_(1)` व `T_(2)` के मध्य कार्यरत है यहाँ कार्यकारी पदार्थ एक आदर्श गैस है

एक पूर्ण चक्र में, गैस द्वारा किया गया कार्य

Options

A. `muRT_(2)log((V_(2))/(V_(1)))-muRT_(1)log((V_(3))/(V_(4)))`
B. `muRT_(1)log((V_(2))/(V_(1)))-muRT_(2)log((V_(3))/(V_(4)))`
C. `muRT_(1)log((V_(2))/(V_(1)))+muRT_(2)log((V_(3))/(V_(4)))`
D. `muRT_(1)log((V_(2))/(V_(1)))+muRT_(2)log((V_(3))/(V_(4)))`

Answer

B

Explanation

`W_("परिणामी")=muRT_(1)log((V_(2))/(V_(1)))-muRT_(2)log((V_(3))/(V_(4)))`
`W_("परिणामी")=W_(AtoB)+W_(BtoC)+W_(CtoD)+W_(DtoA)` (गैस द्वारा कार्य)
`=muRT_(1)log((V_(2))/(V_(1)))+(muR(T_(1)-T_(2)))/(gamma-1)+muRT_(2)log((V_(4))/(V_(3)))+(muR(T_(2)-T_(1)))/(gamma-1)`
`W_("परिणामी")=muRT_(1)log((V_(2))/(V_(1)))-muRT_(2)log((V_(3))/(V_(4)))`