The velocity of a particle executing SHM is `V_1` when displacement is `X_1` and `V_2` when displacement is `x_2`. What is the amplitude of vibration of the particle?

What is the displacement of a particle executing SHM?

A particle executing circular motion of radius 5 m and linear speed of 3 ms^-1 which is increasing at the rate of 2 m s^-2 .What is the acceleration of the particle?

A particle executes S.H.M. Then the graph of velocity as a function of displacement is

The motion of a particle executing simple harmonic motion is described by the displacement function, x(t) = A cos (omegat + phi) . If the initial (t = 0) position of the particle is 1 cm and its initial velocity is omega cm//s , what are its amplitude and initial phase angle ? The angular frequency of the particle is pi s^-1 s If instead of the cosine function, we choose the sine function to describe the SHM : x= B sin (omegat+alpha) , what are the amplitude and initial phase of the particle with the above initial conditions.

Velocity and displacement of a particle executing S.H.M. are out of phase by pi/2 . Explain why?

The velocity-time graph of particle in one dimensional motion is shown in the fig. Which if the following formulae are correct for describing the motion of the pawrticle over the time interval t_1 to t_2 v(t_2) = v(t_1) + a(t_2 - t_2) , v_(average) = ([x(t_2) - x(t_1)])/((t_2 - t_1)) , x(t_2) - x(t_1) = area under the v - t curve. bounded by the t-axis and the dotted line shown.

The displacement of a particle is represented by the equations y = 3 cos (pi/4 - 2omegat) . The motion of the particle is

The displacement of a particle is SHM is x=10 simn(2t-pi/6) meter.When its displacement is 6m,the velocit of the particle (in m s^(-1)) is :