Earth also moves in circular orbit around the sun once every year with an orbital radius of `1.5xx10^(11)m` . What is the accerelation of the earth ( or any object on the surface of the earth) towards the centre of the sun? How does this acceleration compare with `g = 9.8 m//s^(2)`?

Earth can be thought of as a sphere of radius 6400 km.Any object (or a person) is pewrforming circular motion around the axis of the earth due to the earth rotation (period 1 day). What is acceleration of object on the surface of the earth (at equator) towards its centre? What is it at latitude theta ? How does these acceleration compare with g = 9.8 m//s^(2) ?

A satellite of mass 'm' is revolving in a circular orbit of radius 'r' around the earth of mass M. What is the total energy of the satellite?

The radius of the innermost electron orbit of a hydrogen atom is 5.3 xx 10^-11 m . What are radii of the n=2 and n=3 orbits?

A satellite is launched into a circular orbit 1600 km above the surface of the earth. Find the period of revolution, the radius of the earth R = 6400 km and the acceleration due to gravity is 9.8 m//sec^2 .

The radius of the first electron orbit of a hydrogen atom is 0.5overset(@)A . The electron moves in this orbit with a uniform speed of 2.2xx10^(6)m.s^(-1). What is the magnetic field produced at the centre of the nucleus due to the motion of this electron?

In Bohr model of hydrogen atom , the electron circulates around the nucelus in a path of raidus 5.1 xx 10^-11 m at a frequency of 6.8 xx 10^15Hz . What is the value of magnetic field set up at the centre of the orbit?

The acceleration due to gravity on the surface of moon is 1.7 m s^-2 . What isthe time period of a simple pendulum on the surface of moon if itstime period on the surface of earth is 3.5 s? (gon the surface of earth is 9.8 m s6-2 )