A graph of potential energy V (x) versus x is shwon in figure. A particle of energy `E_0` is executing motion in it. Draw graph of velocity and kinetic energy versus x for one complete cycle AFA.

A graph of x versus t is shown in fig. choose corredt alternatives from below.

Draw the graphs of the following inequations: x-y ge 0 .

The potential energy of a certain particle is given by U = 30x^2 - 20 y^2 . Find the force acting on the particle.

Draw the graph of the inequation 3x- 5y +8 ge 0 .

Draw the graph of each of the following equations y+2x=0

Draw the graph of each of the following equations 2x-3y=0

Draw the graph of cos x from 0 to pi and hence find cos 40^@ from the graph.

Draw the graph of y=sin x and y=cosx, 0 le x le 2pi

The potential energy function for a particle executing linear simple harmonic motion is given by V{x) = kx^2//2 , wherek is the force constant of the oscillator. For k = 0.5 N m^-1 , the graph of V[x) versus x is shown in Fig. 6.12. Show that a particle of total energy 1 J moving under this potential must ‘turn back’ when it reaches x =overset+- 2 m.

Draw the graph of the each of the following, 2x+7=0