Home
Class 11
PHYSICS
Derive the expression for moment of iner...

Derive the expression for moment of inertia of a circular disc
about an axis passing through its centre and perpendicular to its plane

Promotional Banner

Topper's Solved these Questions

  • MOTION OF SYSTEM OF PARTICLES AND RIGID BODY

    MBD|Exercise EXERCISE|15 Videos

  • MOTION IN A STRAIGHT LINE

    MBD|Exercise EXERCISE|14 Videos

  • OSCILLATIONS

    MBD|Exercise EXERCISE|11 Videos

Similar Questions

Explore conceptually related problems

Find the expression for moment of inertia of a thin uniform rod about an axis passing through its centre and perpendicular to its length

Find the expression for moment of inertia of a thin uniform rod about an axis passing through its one end and perpendicular to its length.

Find the moment of inertia of a thin circular ring about an axis passing through the centre and perpendicular to the plane of the ring

Derive the expression for moment of inertia of a circular disc about the diameter of the disc.

Derive the expression for moment of inertia of a circular disc about an axis tangential to the plane of the disc.

A thin circular ring od fiameter 15 cm has a mass of 100g.Find its moment of inertia about an axis passing through its centre and perpendicular to its plane.

Define the theorem of parallel axes and apply it to find the moment of inertia of a uniform rod about an axis passing through one of its ends and perpendicular to its length.

Moment of a solid cylinder about its axis of symmetry is equal to moment of inertia about an axis passing through its centre and perpendicular to its length.Show that L//r = sqrt3 .