Three particles, each of mass 'm' are situated at the vertices of an equilateral triangle of side 'a'. the only force acting on the particles are their mutual gravitatinoal foces. It is desired that each particle move on a circle, while maintaining the original mutual separation 'a'. Find the initial velocity that should be given to each particle and also the time period of the circular motion.

Three particles each of mass m are placed at the corners of a right angled triangle as shown in figure if OA=a and OB=b, the position vector of the centre of mass is: .

Three charges of +0.1 C each are placed at the vertices of an equilateral triangle of each side 1m. If the energy is supplied at the rate of 1.0 kw, how many hours would be required to move one of the charges on to the mid point of the line joining the other two? Given =1/(4piepsilon_0) = 9xx 10^9 N ^2C^-2

Three particles, each of mass 1g and carrying a charge q , are suspended from a common point by insulating massless strings , each 100 cm long . if the particles are located at the corners of an equilateral triangle of side 3 cm, calculate the charge q on each particle.

Three forces start acting simultaneously on a particle moving with velocity vecv . There forces are represented in magntiude and direction y three sides of a triangle taken in the same order. The particle will nw move with a velocity

Force on a charge in electric and magnetic fields A charge particle follows a parabolic path in a uniform electric field and a charged particel moving in a uniform magnetic field has two kinds of motions lnear motion in the direction of magnetic field and circular motion in a plane perpendicular to the magnetic field. when charge q is moving perpendicular to the magnetic field B, the radius of the circular path is r=(mv)/(Bq) . If v and B makes an angle theta , then r=(mvsintheta)/(Bq) , and the time period T=(2pim)/(Bq) . Under the influenece of a uniform magnetic field, a charged particles is moving in a circle of radius r with speed v. The time period of motion.

Force on a charge in electric and magnetic fields A charge particle follows a parabolic path in a uniform electric field and a charged particel moving in a uniform magnetic field has two kinds of motions lnear motion in the direction of magnetic field and circular motion in a plane perpendicular to the magnetic field. when charge q is moving perpendicular to the magnetic field B, the radius of the circular path is r=(mv)/(Bq) . If v and B makes an angle theta , then r=(mvsintheta)/(Bq) , and the time period T=(2pim)/(Bq) . When a charged particle q is moving with velocity vecv in a magnetic field vecB , the force is non-zero. It means.

The force vecF experienced by a particle of charge q moving with velocity vecv in a magnetic field vecB is given by vecF=q(vecv xx vecB) , which pair of vectors are always at right angle to each other?

Figure 3.24 gives the x-t plot of a particle in one-dimensional motion. Three different equal intervals of time are shown. In which interval is the average speed greatest, and in which is it the least ? Give the sign of average velocity for each interval.

An alpha particle (_2He^4) is moving directly towards a stationary gold nucleus (_(79)Au^(197)) .The alpha -particle and the gold nucleus may be considered to be solid spheres with the charge and mass concentrated at the centre of each sphere.When the two spheres are just toching,the sepaation of their centres is 9.6 xx 10^(-15) m . the alpha particle and the gold nucleus may be assumed to be an isolatedd system.Calculate for the alpha particle just in contact with the gold nucleus, its electric potential energy.