Assuming the earth to be a sphere of uniform mass density, how much would a body weigh half way down to the centre of the earth if it weighed 250 N on the surface ?

What will be the corresponding expression for the energy needed to completely diassemble the planet earth against the gravitational pull amongst its constituent particles? Assume the earth to be a sphere of uniform mass density. calculate the energy, given that the product of the mass and the radius of the earth to be 2.5xx10^(31)kg-m

Assuming the earth to be a sphere of radius 6370 km, how many square kilometers is area of the land, if three-fourth of the earth’s surface is convered by water.

If a man weighs 250 N on the surface of earth, what will his wight half way down to the centre of earth which is sipposed to be spherical of uniform mass density.

The centre of mass of an extended body on the surface of the earth and its centre of gravity

An object weighs 10 N when measured on the surface of the earth. What would be its weight when measured on the surface of the moon?

If a planet existed whose mass and radius were both half of that of the eawrth. What would be the acceleration due to gravity at the surface of the planet in terms of that on the surface of the earth?

Earth can be thought of as a sphere of radius 6400 km.Any object (or a person) is pewrforming circular motion around the axis of the earth due to the earth rotation (period 1 day). What is acceleration of object on the surface of the earth (at equator) towards its centre? What is it at latitude theta ? How does these acceleration compare with g = 9.8 m//s^(2) ?