A 14.5 kg mass, fastened to the end of a steel wire of unstretched length 1.0 m, is whirled in a vertical circle with an angular velocity of 2 `rev//s` at the bottom of the circle. The cross-sectional area of the wire is 0.065 `cm^2`. Calculate the elongation of the wire when the mass is at the lowest point of its path.

A copper wire of resistivity 1.6xx10^-8 ohm-m has a cross sectional area of 20xx10^-4 cm^2 . Calculate the length of wire required to make a 10 ohm coil.

A small stone of mass 200 g is tied to one end of a string of length 80 cm . Holding the other end in hand , the stone is whirled into a vertical circle What is the minimum speed that needs to be imparted at the lowest point of the circular path , so that the stone is just able to complete the vertical circle ? what would be the tension at the lowest point of circular path ? (Take g = 10 m//s^(2) ) .

A body weighing 0.4 kg is whirled in a vertical circle making 2 revolutions per second .If the radius of the circole is 1.2m,fing the tension in the sting when the body is (a) at thge top of the circle .(b) at the bottom of the circle.

A stell wire of length 4 m ,is stretched through 2 mm ,.The corss - sectional area of the wire is 2.0 mm^2 .If young's modulus of steel si 2.0 xx 10 ^11 N//^2 find the energy density of the wire

A stell wire of length 4 m ,is stretched through 2 mm ,.The corss - sectional area of the wire is 2.0 mm^2 .If young's modulus of steel si 2.0 xx 10 ^11 N//^2 find The elastic potential energy stored in the wire.

The stone of mass 100 g is suspended from the end of a weightless string of length 100 cm and is allowed to swing in a vertical plane.The speed of the mass is 2 m s^-1 when the string makes an angle of 60^@ with the vertical .Calculate the tension in the string at theta = 60^@ .Also,caculate the speed of the stone when it is in the lowest poition. (g=9.8 m s^(-2) ) .

Two wires of diameter 0.25 cm, one made of steel and the other made of brass are loaded as shown in Fig. 9.13. The unloaded length of steel wire is 1.5 m and that of brass wire is 1.0 m. Compute the elongations of the steel and the brass wires:

A rod of length 1.05 m having negligible mass is supported at its ends by two wires of steel (wire A) and aluminium (wire B) of equal length as shown in the figureThe cross sectional area of wires A and B are 1.0 mm^2 and 2.0 mm^2 , respectivley. AT wat point along the rod should a mass m be suspended in order to produce equal strains in both steel and aluminium wires?

A rod of length 1.05 m having negligible mass is supported at its ends by two wires of steel (wire A) and aluminium (wire B) of equal lengths as shown in Fig. 9.15. The cross-sectional areas of wires A and B are 1.0 mm^2 and 2.0 mm^2 , respectively. At what point along the rod should a mass m be suspended in order to produce equal strains in both steel and aluminium wires.:

A rod of length 1.05 m having negligible mass is supported at its ends by two wires of steel (wire A) and aluminium (wire B) of equal length as shown in the figure The cross sectional area of wires A and B are 1.0 mm^2 and 2.0 mm^2 , respectivley. AT wat point along the rod should a mass m be suspended in order to produce .equal stresses.