The density of air in atmoshpere decreases with height and can be expressed by the relaton `rho = rho_0e^(-alphah` where `rho_0` is the density at sea level , `alpha` is a constant and h is the height, Calculate the atmospheric pressure at sea level. Assume g to be constatn. The numerical values of constants are : `g = 9.8 ms^-2 , rho_0 = 1.3 kg m^-3 , alpha = 1.2 xx 10^-4 m^-1`

It is known that density rho of air decreases with height y (in metres) as : rho = rho_(0) e^(-y//y_0) where rho_0 = 1.25 kg m^-3 is the density at sea level and y_0 is a constant. This density variation is called the law of atmospheres. Obtain this law assuming the temperature of atomoshpere remains constant (isothermal conditions). Also assume that the value of g remains constant.

Give the oppositesof : Height above sea level.

If the resistivity of an alloy is rho' and that of constituent metals is rho , then

If alpha is a complex constant such that alpha z^2+z+bar( alpha)=0 has a real root, then

What is the relation between pressure P and density rho of a gas at constant temperature?

From the relation R = R_0A^(1/3) , where R_0 is a constant and A is the mass number of a nucleus, show that the nuclear matter density is nearly constant (i.e. independent of A).

Check the correctness of the relation : v=sqrt((E )/(rho)) where the symbols have their usual meanings.

Explain why Atmospheric pressure at a height of about 6 km decreases to nearly half of its value at the sea level, though the height of the atmosphere is more than 100 km

What is the density of water at a depth where pressure is 80.0 atm, given that its density at the surface is 1.03 xx 103 kg m^-3 ?