When a resistor of `20 Omega` is connected in series with a battery, the current is 0.5 A. when a resistor of `10 Omega` is connected the current becomes 0.8 A. calculate the emf and the internal resistance of the battery.

A galvanometer, together with an unknown resistance in series, is connected across two identical batteries of each 1.5 V. When the batteries are connected in series,the galvanometer records a current of 1 A, and when the batteries are connected in parallel, the current is 0.6 A. In this case, the internal resistance of the battery

The resistance of each arm of the wheat stone bridge is 10Omega . A resistance of 10Omega is connected in series with galvanometer then the equivalent resistance across the battery will be

A current of 2A flows through a 2 ohm resistor when connected across a battery , the same battery supplies a current of 0.5A when connected across a 9 ohm resistor . the internal resistance of the battery is

A cell of emf epsilon and internal resistance r gives a current of 0.5 A with an external resistance of 12 Omega and a current of 0.25 A with an external resistance of 25 Omega. Calculate (a) internal resistance of the cell

A storage battery of a car has e.m.f of 12 V. The maximum current that can be drawn from the battery is 24A. Calculate the internal resistance of the battery.

A battery of e.m.f 6 V is connected to a resistor of 100 Omega through an ammeter of resistance 2Omega . If 50 mA current flows through resistor, find the itnernal resistance of the battery.

A cell of emf epsilon and internal resistance r gives a current of 0.5 A with an external resistance of 12 Omega and a current of 0.25 A with an external resistance of 25 Omega. Calculate (b) emf of the cell.