A spherical rubber balloon carries a charge that is uniformally distributed over its surface. As the balloon is blown up and increase in size, how does the total electric flux coming out of the surface change? Give reason.

Show that total electric flux over a closed surface due to charge outside the surface is zero?

A spherical conductor of radius 12 cm has a charge of 1.6 xx 10^-7C distributed uniformly on its surface. What is the electric field inside the sphere?

A spherical conductor of radius 12 cm has a charge of 1.6 xx 10^-7C distributed uniformly on its surface. What is the electric field just outside the sphere?

A spherical conductor of radius 12 cm has a charge of 1.6 xx 10^-7C distributed uniformly on its surface. What is the electric field at a point 18 cm from the centre of the sphere?

Consider the charge configuration and a spherical Gaussian surface as shown in the figure. When calculating the flux of the electric field over the spherical surface, the electric field will be due to.

If the charge distribution within Gaussian surface is changed, but total charge inside it remains unchanged, will there be any change in the electric field strength outside inside the Gaussian surface?

A thin metallic spherical shell of radius R carries a charge Q on its surface. A point charge Q/2 is placed at its centre C and another charge +2Q outside the shell at a distance r from the centre as shown in figure. Find the electric flux through the shell.

Electric field is the electrostatic force per unit charge acting on a vanishingly small test charge placed at that point. It is a vector quantity and the electric field inside a charged conductor is zero. Electric flux phi is the total number of electric lines of force passing through a surface in a direction normal to the surface when the surface is placed inside the electric field. phi=ointvecE.vec(ds)=q/epsilon_0 A positive charge Q is uniformly distributed along the circular ring of radius R. A small test charge q is placed at the centre of te ring as shown.