Two dielectric slabs of dielectric constants `K_1` and `K_2` are filled in between two plates each of area A, of a parallel plate capacitor. Find net capacitance.

Two dielectric slabs of dielectric constant K_1 and K_2 are filled in between the two plates, each of area A, of the parallel plate capacitor as shown in the figure. What will be the capacitance of the capacitor

A parallel plate capacitor, each with plate area A and separation d is charged to a potential difference V. The battery used to charge it is then disconnected. A dielectric slab if thickness d and dielectric constant K is now placed between the plates. what change, if any will take place in capacitance?

A parallel plate capacitor, each with plate area A and separation d is charged to a potential difference V. The battery used to charge it is then disconnected. A dielectric slab if thickness d and dielectric constant K is now placed between the plates. what change, if any will take place in electric field intensity between the plates.

Figure shows two identical capacitors C_1 and C_2 each of 1 mu F capacitance connected to a battery of 6 V. initially switch S is closed. After sometime S is left open and dielectric slab of dielectric constant k = 3 are inserted to fill completely the space between the plates of the two capacitors. How will the potential difference between the plates of the capacitors be affected after the slabs are inserted?

A parallel plate capacitor, each with plate area A and separation d is charged to a potential difference V. The battery used to charge it is then disconnected. A dielectric slab if thickness d and dielectric constant K is now placed between the plates. what change, if any will take place in charge on plates?

Figure shows two identical capacitors C_1 and C_2 each of 1 mu F capacitance connected to a battery of 6 V. initially switch S is closed. After sometime S is left open and dielectric slab of dielectric constant k = 3 are inserted to fill completely the space between the plates of the two capacitors. How will the Charge between the plates of the capacitors be affected after the slabs are inserted?

On what factors does the capacitance of a parallel plate capacitor with dielectric depend?

For a given potential difference, does a capacitor store more or less charge with a dielectric than it does without a dielectric constant (K) is inserted between the two plates of capacitor. What is the new of charge stored in the capacitor?