A uniform electric field E exists between two charged plates as shown in Fig.HQ 2. What would be the work donw in moving a charge q along the closed rectangular path ABCDA?

A uniform field E exists between two charged plates as shown in the figure. What would be the work done in moving a charge q along the closed rectagnualr path ABCDA?

A uniform electric field exists between two charged plates shown in the figure VSAQ 40. what should be the work done in moving a charge q along the closed recatangular path ABCDA?

Show that the work done in moving a unit charge along a closed path is zero.

Prove that the work done in moving a unit charge along a closed path in an electric field is zero?

What will be the path of a charged particle moving along the direction of a uniform magnetic field?

Force on a charge in electric and magnetic fields A charge particle follows a parabolic path in a uniform electric field and a charged particel moving in a uniform magnetic field has two kinds of motions lnear motion in the direction of magnetic field and circular motion in a plane perpendicular to the magnetic field. when charge q is moving perpendicular to the magnetic field B, the radius of the circular path is r=(mv)/(Bq) . If v and B makes an angle theta , then r=(mvsintheta)/(Bq) , and the time period T=(2pim)/(Bq) . When a charged particle q is moving with velocity vecv in a magnetic field vecB , the force is non-zero. It means.

Force on a charge in electric and magnetic fields A charge particle follows a parabolic path in a uniform electric field and a charged particel moving in a uniform magnetic field has two kinds of motions lnear motion in the direction of magnetic field and circular motion in a plane perpendicular to the magnetic field. when charge q is moving perpendicular to the magnetic field B, the radius of the circular path is r=(mv)/(Bq) . If v and B makes an angle theta , then r=(mvsintheta)/(Bq) , and the time period T=(2pim)/(Bq) . Under the influenece of a uniform magnetic field, a charged particles is moving in a circle of radius r with speed v. The time period of motion.

A particle of mass m and charge (-q) enters the region between the two charged plates initially moving along x-axis with speed v_x. The length of plate is L and an uniform electric field E is maintained between the plates. Show that the vertical deflection of the particle at the far edge of the plate is qEL^2//(2m v_x^2) .