A wire of resistance `1 Omega` is stretched to double its length. What is the new resistance?

A wire of resistances 1 Omega is streched to double its length. What is the new resiatnce?

A 8 ohm resistance wire is stretched to double its length. Calculate the new resistance of the wire.

A metallic wire of resistane of 40Omega is stretched to twice its length. Its new resistance would be approximately.

A wire of resistivity rho is stretched to double its length. Then its new resistivity will:

A wire of resistivity rho is streched to double its length. Then its new resistivity will:

A wire of resistance 8 Omega is bent in the form of a circle. What is the effective resistance between the ends of a diameter of this circle.

A uniform copper wire of mass 2.23xx10^(-3) kg carries a current of 1 A when 1.7 V is applied across it. Calculate its length and area of cross-section. If the wire is uniformly stretched to double its length, calculate the new resistance. Density of copper is 8.92xx10^(3) kg m^(-3) and resistivity is 1.7xx10^(-8) Omega m.