How will you use potentiometer to determine internal resistances of a cell?

The following circuit shows the use of potentionmeter to measure the internal resistance of a cell. When the key K is open, how does the balance point change if the current from the driver cell decreases?

The following circuit shows the use of potentionmeter to measure the internal resistance of a cell.When the key K is closed, how does the balance point change if R is increased keeping current from the driver cell constant?

Figure 3.35 shows a 2.0 V potentiometer used for the determination of internal resistance of a 1.5 V cell. The balance point of the cell in open circuit is 76.3 cm. When a resistor of 9.5 Omega is used in the external circuit of the cell, the balance point shifts to 64.8 cm length of the potentiometer wire. Determine the internal resistance of the cell. :

What is the principle of a potentiometer? With the help pf circuit diagram, explain the use of potentiometer to measure internal resistance of a given primary cell.

When a balance point is obtained in a potentiometer for finding the internal resistance of a cell, the current through the potentiometer wire is due to

Derive the expression for internal resistance of a cell.

On what factor does the internal resistance of a cell depends?