The figure TBQ 9.38 shows an equiconvex lens (of refractive index 1.50) in contact with a liquid layer on top of a plane mirror. A small needle with its tip on the principal axis is moved along the axis until its inverted images if found at the positions of hte needle. The distance of the needle from the lens is measured to be 45.0 cm. The new distane is measured to be 30.0 cm. What is the refractive index of the liquid?

Define the principal axis of a lens.

An equiconvex lens with radii of curvature of magnitude R each,is put over a liquid layer poured on top of a plane mirror.A small needle ,with its tip on the principal axis of the lens,is moved along the axis until its inverted real image coincides with the needle itself.The distance of the needle from the lens is measured to be a as shown in Fig.2.53. On removing the liquid layer and repeating the ezperiment,the distance is found to be b as shown in Fig.254 .Gien that tow values of distances meeawured reepresent the focal length values in the two cases, obtain a formula for the refractive index of the liquid. .

What happens when a convex lens of refractive index 1.2 is immersed in a liquid of refractive index 1.3?

Explain what happens ,when a convex lens of refractive index 1.2 is immersed in a liquid of refractive index 1.3.

A dip needle with a circular scale is mounted on a horizontal axis. How can the direction of the magnetic meridian be found with the help of this needle?

A convex lens of refractive index 1.5 is immersed in a liquid of refractive index: 1.6 What will happen to the focal length and nature of lens ?

Converging lens of refractive index 1.5 is kept in a liquid medium having the same refractive index what would be the focal length of the lens in this medium?