An `alpha`-particle of 10MeV collides head on with a copper nucleus (Z=29) and returns on its original path. What conclusion would your draw about between the centres of the particle and nucleus

An alpha particle having 12.5 MeV kinetic energy collides with copper nucleus (Z=29) and retraces it s path .What is the size of the nucleus? Given, 1/(4 pi e_0) = 9 xx 10^9 N m^2 C^(-2) .

An alpha particle (_2He^4) is moving directly towards a stationary gold nucleus (_(79)Au^(197)) .The alpha -particle and the gold nucleus may be considered to be solid spheres with the charge and mass concentrated at the centre of each sphere.When the two spheres are just toching,the sepaation of their centres is 9.6 xx 10^(-15) m . the alpha particle and the gold nucleus may be assumed to be an isolatedd system.Calculate for the alpha particle just in contact with the gold nucleus, its electric potential energy.

The nucleus of an atom of ._(92)Y^(235) initially at rest decays by emitting an alpha particle. The binding energy per nucleon of parent and dougther nuclei are 7.8MeV and 7.835MeV respectively and that of alpha particles is 7.07MeV//"nucleon". Assuming the dougther nucleus to be formed in the unexcited state and neglecting its share of energy in the reaction, calculate speed of emitted alpha particle. Take mass of alpha particle to be 6.68xx10^(-27)kg .

A small stone, of mass 0.2 kg, tied to a massless, inextensible string, is rotated in vertical circle of radius 2 m. if the particle is just able to complete the vertical circle, what is its speed at the highest point of its circular path? How would this speed get effected if the mass of the stone is increased by 50%? (Take g = 10 ms^(-2) )

A nucleus at rest undergoes a decay emitting an alpha -particle of de-broglie wavelength lambda = 5.76 xx 10^(-15) m . The mass of daughter nucleus is 223.40 amu and that of alpha-particle is 4.002 a.m.u.detrmine the total kinetic energy in the final state.Hence,obtain teh mass of the parent nucleus in a.m.u. Given that 1 a.m.u.=931.470 MeV .

The extent of localisation of a particle is determined roughly by its de-Broglie wave.If an electron is loclalized within the nucleus (of size about 10^(-14)m) of an atom,what is its energy?Compare this energy with the typicla binding energyies(of the order of a few Me) in a nucleus and hyence argue why electrons cannot reside in a nucleus.

A copper atom consists of copper nucleus surrounded by 29 electrons. The atomic weight of copper is 63.5mol e^(-1) . Let us now take two pieces of copper each weighing 10g. Let us trandfer one elcetron from one piece to another for every 100 atoms in that piece. What will be the Coulomb force between the two pieces after the trandfer of electrons, if they are 1cm apart? Avogadro number= 6xx10^(23) mol e^(-1) , charge on an electron =- 1.6xx10^(-19)C.

An alpha particle having kinetic energy equal to 8.7 MeV is projected towards the nucleus of copper with Z=29.Calculate its distance of closet approach.