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The nucleus "10^23Ne decays by beta^-em...

The nucleus `"_10^23Ne` decays by `beta^-`emission. Write down the `beta`-decay equation and determine the maximum kinetic energy of the electrons emitted. Given that: m ( `"_10^23 Ne` ) = 22.994466 u m ( `"_11^23 Na` ) = 22.989770 u.

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