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From the relation R = R0A^(1/3), where R...

From the relation `R = R_0A^(1/3)`, where `R_0` is a constant and A is the mass number of a nucleus, show that the nuclear matter density is nearly constant (i.e. independent of A).

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Size of nucleus was obtained by the equation r=R_(0)A^(1//3) , Where r is the radius of nucleus of mass no A. and R_(0) is a constant whose valie is equal to 1.5xx10^(-15) metre. (Given : 1 amu = 1.66xx10^(-24)g ) What is the density of a nucleus of mass number A ? a) (4)/(3)pi(1.5xx10^(-15))^(3) A b) 1.17xx10^(17)kg//cm^(3) c) 1.17xx10^(17)kg//m^(3) d) none of these

Size of nucleus was obtained by the equation r=R_(0)A^(1//3) , Where r is the radius of nucleus of mass no A. and R_(0) is a constant whose valie is equal to 1.5xx10^(-15) metre. (Given : 1 amu = 1.66xx10^(-24)g ) Nucleus radius of ._(6)C^(12) is 3xx10^(-15) metre. What is density ratio of d_(c)//d_(H_(2)O) ? a) 1.76xx10^(17) b) 1.76xx10^(14) c) 17.6xx10^(7) d) 17.6xx10^(17)

Let R be a relation defined by R = {(a, b) : a ge b }, where a and b are real numbers, then R is