Obtain the maximum kinetic energy of `beta`-particles, and the radiation frequencies of `gamma` decays in the decay scheme shown in Fig. 13.6. You are given that m( `"^198Au`) = 197.968233 u m(`"^198Hg`) =197.966760 u :

Find the Q-value and the kinetic energy of the emitted a-particle in the alpha -decay of - "_88^226Ra .Given m ( "_88^226Ra ) = 226.02540 u and m ( "_86^222Rn ) = 222.01750 u.

Find the Q-value and the kinetic energy of the emitted a-particle in the a-decay of - "_86^220Rn .Given m ( "_86^220Rn ) = 220.01137 u, m ( "_84^216Po ) = 216.00189 u.

The nucleus "_10^23Ne decays by beta^- emission. Write down the beta -decay equation and determine the maximum kinetic energy of the electrons emitted. Given that: m ( "_10^23 Ne ) = 22.994466 u m ( "_11^23 Na ) = 22.989770 u.

A nucleus at rest undergoes a decay emitting an alpha -particle of de-broglie wavelength lambda = 5.76 xx 10^(-15) m . The mass of daughter nucleus is 223.40 amu and that of alpha-particle is 4.002 a.m.u.detrmine the total kinetic energy in the final state.Hence,obtain teh mass of the parent nucleus in a.m.u. Given that 1 a.m.u.=931.470 MeV .

The radionuclide "^11C decays according to "_6^11C rarr "_5^11B + e^+ + v : T_(1/2) = 20.3 min .The maximum energy of the emitted positron is 0.960 MeV. Given the mass values: m ( "_6^11C ) = 11.011434 u and m ( "_6^11B ) = 11.009305 u, calculate Q and compare it with the maximum energy of the positron emitted.