A piece of wood from the ruins of an ancient building was found to have a `"^14C` activity of 12 disintegrations per minute per gram of its carbon content. The `"^14C` activity of the living wood is 16 distintegrations per minute per gram. How long ago did the tree, from which the wooden sample came, die? Given half-life of `"^14C` is 5760 years.

A piece of wood from an archaeological source has a "^14C activity which ls 60% of the activity found in fresh wood today. Calculate the age of the archaeological sample (the half life period of C-14 is 5770 years).

The normal activity of living carbon-containing matter is found to be about 15 decays per minute for every gram of carbon. This activity arises from the small proportion of radioactive "_6^14C present with the stable carbon isotope "_6^12C . When the organism is dead, its interaction with the atmosphere (which maintains the above equilibrium activity) ceases and its activity begins to drop. From the known half-life (5730 years) of "_6^14C , and the measured activity, the age of the specimen can be approximately estimated. This is the principle of "_6^14C dating used in archaeology. Suppose a specimen from Mohenjodaro gives an activity of 9 decays per minute per gram of carbon. Estimate the approximate age of the Indus-Valley civilisation.

The half-life for radioactive decay of .^14C is 5730 years. An archaeological artifact contented wood that has only 80% of the .^14C found in living tree. Estimate the age of the sample.

The half life period for radioactive decay of ""^(14)C is 5670 years. An archaeological artifact contained wood had only 80 % the ""^(14)C found in a living tree. Estimate the age of the sample.

A sample of 16 g charcoal was brought into contact with CH_(4) gas contained in a vessel of 1 litre at 27^(@) C . The pressure of gas was found to fall from 760 to 608 torr. The density of chacoal sample is 1.6 g//m^(3) . What is the volume of the CH_(4) gas adsorbed per gram of the adsorbent at 608 torr and 27^(@)C ? 125 L//g , 16.25 mL//g , 26 mL//g , none of these .