Home
Class 12
PHYSICS
A neutron is absorbed by "3^6Li nucleus ...

A neutron is absorbed by `"_3^6Li` nucleus with the subsequent emission of an `alpha-particl e`.Write down the corresponding reaction.

Promotional Banner

Similar Questions

Explore conceptually related problems

A neutron is abosorbed by "_3^6Li nucleus with the subsequent emission of an alpha-particl e . Calculate the energy released in MeV in this reaction given "_3^6Li =6.015126 u, mass (neutron)=1.0086654 u mass (alpha)=4.0026044 u and mass (triton)=3.0100000u. Take 1u=931 MeV//c^2 .

A nucleus "_nX^m emit one alpha-particl e and two beta-particl e the resulting nucleus is

Under certain circumstances, a nucleus can decay by emitting a particle more massive than an alpha -particle. Consider the following decay processes: "_88^223Ra rarr "_82^209Pb + "_6^14C , "_88^223Ra rarr "_86^219Rn + "_2^4He .Calculate the Q-values for these decays and determine that both are energetically allowed.

Does the ratio of neutrons to protons in a nucleus increase, decrease or remain the same after the emission of alpha-particl es .

When a deuton of mass 2.0141 u and neglible kinetic energy is absorbed by lithium ("_3^6Li) of nucleus of mass 6.0155 u, the compound nucleus disintegrates spontaneously into two alpha particles, each of mass 4.0026u. Calculate the energy in joules by each alpha particle. (1u=1.66 xx 10^-27kg)

Strontium-90 decays with the emission of a beta- particle to form Ytrium-90 .The reaction is represented by the equation _(38)Sr^(90) rarr _(39)Y^(90) + _(-1)e^0 + 0.55 MeV the decay constant is 0.025 year ^(-1) . Suggest,with a reason,which nucleus _(38)Sr^(90) or _(39)Y^(90) ,has the greater binding energy.

A radioactive nucleus is represneted by the symbol _bX^a ,How is the new ucleus represented after the emission of an alpha particle

An alpha particle (_2He^4) is moving directly towards a stationary gold nucleus (_(79)Au^(197)) .The alpha -particle and the gold nucleus may be considered to be solid spheres with the charge and mass concentrated at the centre of each sphere.When the two spheres are just toching,the sepaation of their centres is 9.6 xx 10^(-15) m . the alpha particle and the gold nucleus may be assumed to be an isolatedd system.Calculate for the alpha particle just in contact with the gold nucleus, its electric potential energy.

The nucleus of an atom of ._(92)Y^(235) initially at rest decays by emitting an alpha particle. The binding energy per nucleon of parent and dougther nuclei are 7.8MeV and 7.835MeV respectively and that of alpha particles is 7.07MeV//"nucleon". Assuming the dougther nucleus to be formed in the unexcited state and neglecting its share of energy in the reaction, calculate speed of emitted alpha particle. Take mass of alpha particle to be 6.68xx10^(-27)kg .

If R is a relation "is divisor of" from the set A = {1, 2, 3} to B = {4, 10, 15}, write down the set of ordered pairs corresponding to R.