Radioactive element A are being produced at a constant rate `alpha`. The element has a decay constant `lambda`. At time t=0, there are `N_0` nuclei of the element.
If `alpha=2N_0lambda`, calculate the number of nuclei of A after one half life of A and also limiting value of N as `t rarr infty`.

Radioactive element A are being produced at a constant rate alpha . The element has a decay constant lambda . At time t=0, there are N_0 nuclei of the element. Calculate the number of nuclei A at time t.

A radioactive nuclide is produced at a constant rate of alpha per second . It’s decay constant is lambda . If N_(0) be the no. of nuclei at time t=0 , then max. no. nuclei possible are : a) N_(0) b) alpha//lambda c) N_(0)+(alpha)/(lambda) d) (lambda)/(sigma)+N_(0)s

There are two radioactive substances A and B. Decay constant of B is two times that of A. Initially both have equal numbr of nuclei. After n half lives of A, rate of disintegration of both are equal. Find the value of n.

, At time t=0, intial mole of A is 1. Overall half time of the reaction is 15 days. Then calculate the number of mole of C after 45 days if the raio of k_(1):k_(2):k_(3) is 4:2:1

A radioactive nucleus X decays to a nucleus Y with a decay constant lambda_X=0.1s^-1, Y further decays to a stable nucleus Z with a decay constant lambda_Y=1//30s^-1 . Initially, there are only X nuclei and their number is N _0=10^20 . Set up the rate equations for the populations of X, Y and Z. The population of Y nucleus as a function of time is given by N_Y(t)={N _0lambda_X//(lambda_X-lambda_Y)}[exp(-lambda_Yt)-exp(-lambda_Xt)]. Find the time at which N_Y is maximum and determine the population X and Z at that instant.

Starting from 10g of a radioactive element, 0.25 g was left after 5 years. Calculate Rate constant for the decay of the radioactive element.

Starting from 10g of a radioactive element, 0.25 g was left after 5 years. Calculate The time required for half of the element to decay.

There are two radio nuclei A and B is a alpha -emitter and B is beta -emitter. Their disintegration constant are in the ratio of 1:2 . What should be the number of atoms ratio of A and B at time t=0 , so that initially probability of getting of alpha and beta -particles are same.

Radioactive disintegration is a first order reaction and its rate depends only upon the nature of nucleus and does not depend upon external factors like temperature and pressure. The rate of radioactive disintegration (Activity) is represented as -(dN)/(dt)=lambdaN Where lambda= decay constant, N= number of nuclei at time t, N_(0) =intial no. of nuclei. The above equation after integration can be represented as lambda=(2.303)/(t)log((N_(0))/(N)) Calculate the half-life period of a radioactive element which remains only 1//16 of its original amount in 4740 years: a) 1185 years b) 2370 years c) 52.5 years d) none of these