Home
Class 12
PHYSICS
A semiconductor has equal electron and h...

A semiconductor has equal electron and hole concentration of `6 xx 10^4m^-3`. On doping with a certain impurity electron concentration increases to `8xx10^12m^-3`. Identify the type of semiconductor?

Promotional Banner

Similar Questions

Explore conceptually related problems

A semiconductor has equal electron and hole concentration 6xx10^8 m^(-3) .On doing with a certain impurity,electron concentration increases to 8xx10^(12) m^(-3) .Identify the type of semicondcutor after doping.

A semiconductor has equal electron and hole concentration of 4.2 xx 10^8 m^(-3) .On doping with a certain impurity,electron concentration increases to 6xx10^(12)m^(-3) . identify the new seiconductor obtained after doping.

A semiconductor has equal electron and hole concentration of 2 xx 10^8 m^(-3) .On doping with a certain impurity,electron concentration increases to 4xx10^(10)m^(-3) . What type of semiconductor is obtained on doping?

A semiconductor has equal electron and hole concentration of 6 xx 10^8m^-3 . On doping with a certain impurity electron concentration increases to 9xx10^12m^-3 Calculate the new hole concentration.

Pure Si at 500 K has equal electron n_e and hole n_h concentration of 1.5 xx 10^16 m^-3 . Doping by Indium increases n_h to 4.5 xx 10^22 m^-3 . The doped semiconductor is of

A semiconductor has electron concentration of 8 xx 10^8 m^(-3) . and hole concentration 4xx10^(10)m^(-3) .Is this semiconductor p-type or n-type?

A semiconductor is known to have an electron concentration of 8 xx 10^(13) cm^(-3) and a hole concentration of 5 xx 10^(12) cm^(-3) . Is the semiconductor n type or p-type?

A semiconductor has electron concentration of 8 xx 10^-13 cm^-3 and hole concentration of 4 xx 10^-12 cm^-3 . Is the semiconductor p-type or n-type ?

A semiconductor has electron concentration of 4xx10^12 cm^-3 and hole concentration of 7xx10^-3 cm^-3 . Is the semiconductor n-type or p-type ?

A semiconductor has electron concentration of 8 xx 10^-13 cm^-3 and hole concentration of 4 xx 10^-12 cm^-3 .Calculate conductivity of the sample if electron mobility = 24000 cm^2V^-1 s^-1 and hole mobility = 200 cm^2 V^-1 s^--1 and e = 1.6 xx 10^-19C .