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In a p-n junction diode, the current I c...

In a p-n junction diode, the current I can be expressed as `I = I_0 exp ((eV)/(2k_BT))` where `I_0` is called the reverse saturation current, V is the voltage across the diode and is positive for forward bias and negative for reverse bias, and I is the current through the diode, `k_B` is the Boltzmann constant `(8.6xx 10^-5 (eV)/K)` and T is the absolute temperature. If for a given diode ` I_0 = 5 xx 10^-12 A` and T = 300 K, then - What will be the increase in the current if the voltage across the diode is increased from 0.6 V to 0.7 V?

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In a p-n junction diode, the current I can be expressed as I = I_0 (exp ((eV)/(2k_BT))-1) where I_0 is called the reverse saturation current, V is the voltage across the diode and is positive for forward bias and negative for reverse bias, and I is the current through the diode, k_B is th Boltzmann constant (8.6xx 10^ -5 eV/K) and T is the absolute temperature. If for a given diode I_0 = 5 xx 10^ -12 A and T = 300 K, then - What will be the forward current at a forward voltage of 0.6 V?

In a p-n junction diode, the current I can be expressed as I = I_0 (exp ((eV)/(2k_BT))-1) where I_0 is called the reverse saturation current, V is the voltage across the diode and is positive for forward bias and negative for reverse bias, and I is the current through the diode, k_B is th Boltzmann constant (8.6xx 10^-5 eV/K) and T is the absolute temperature. If for a given diode I_0 = 5 xx 10^ -12 A and T = 300 K, then - What will be the current if reverse bias voltage changes from 1 V to 2 V?

In a p-n junction diode, the current I can be expressed as I = I_0 exp ((eV)/(2k_BT)) where I_0 is called the reverse saturation current, V is the voltage across the diode and is positive for forward bias and negative for reverse bias, and I is the current through the diode, k_B is th Boltzmann constant (8.6xx 10^-5 (eV)/K) and T is the absolute temperature. If for a given diode I_0 = 5 xx 10^-12 A and T = 300 K, then - What is the dynamic resistance when the voltage is increased to 0.7 V from 0.6 V?

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