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Let alpha,beta be the roots of the equat...

Let `alpha,beta` be the roots of the equation `(x-a)(x-b)=c ,c!=0` Then the roots of the equation `(x-alpha)(x-beta)+c=0` are

A

(a) `a ,c`

B

(b) `b ,c`

C

(c) `a ,b`

D

(d) `a+c ,b+c`

Text Solution

Verified by Experts

Since `alpha, beta` are the roots fo
`(x-a)(x-b)=c`
or `(x-a)(x-b)-c=0`
Then `(x-a)(x-b)-c-(x-alpha)(x-beta)`
`implies(x-alpha)(x-beta)+c=(x-a)(x-b)`
Hence roots of `(x-alpha)(x-beta)+c=0` are a,b.
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