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Find n, if (n+2)!=60xx(n-1)!...

Find n, if `(n+2)!=60xx(n-1)!`

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`because(n+2)!=(n+2)(n+1)n(n-1)!`
`implies((n+2)!)/((n-1)!)=(n+2)(n+1)n`
`implies60=(n+2)(n+1)n` [given]
`implies5xx4xx3=(n+2)xx(n+1)xxn`
`thereforen=3`
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