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If .^(2n)C(3):^(n)C(3)=11:1, find the va...

If `.^(2n)C_(3):^(n)C_(3)=11:1`, find the value of n.

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We have, ltBrgt `.^(2n)C_(3):^(n)C_(3)=11:1`
`implies(.^(2n)C_(3))/(.^(n)C_(3))=(11)/(1)`
`implies((2n(2n-1)(2n-2))/(1*2*3))/((n(n-1)(n-2))/(1*2*3))=11implies(4(2n-1))/((n-2))=11`
`implies8n-4=11n-22implies3n=18`
`thereforen=6`
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