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If f : A rarr B is a bijective function,...

If f : A `rarr` B is a bijective function, then `f^(-1) of` is equal to

A

`fof^(-1)`

B

`f`

C

`f^(-1)`

D

`I_(A)` (the identity map of the set A)

Text Solution

Verified by Experts

The correct Answer is:
D
`f : A rarr B`
f is a function, then `f^(-1)` is also a bijective function. Composite function `(f^(-1) of) = I_(A)`
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