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In a DeltaABC, if 2AC=3CB, then 2OA+3OB ...

In a `DeltaABC`, if `2AC=3CB,` then `2OA+3OB` is equal to

A

5OC

B

`-OC`

C

`OC`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
A
`2OA+3OB=2(OC+CA)+3(OC+CB)`
`=5OC+2CA+3CB=5OC(because2CA=-3CB)`.
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