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ABCD is a parallelogram whose diagonals ...

`ABCD` is a parallelogram whose diagonals meet at P. If O is a fixed point, then `bar(OA)+bar(OB)+bar(OC)+bar(OD)` equals :

A

OP

B

2OP

C

3OP

D

4OP

Text Solution

Verified by Experts

The correct Answer is:
D
We know that, P will be the mid-point of AC and BD.

`thereforeOA+OC=2OP` . . . (i)
and `OB+OD=2OP`
On adding Eqs. (i) and (ii), we get
`OA+OB+OC+OD=4OP`
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