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In a regular hexagon ABCDEF, vec(AB)=a, ...

In a regular hexagon ABCDEF, `vec(AB)=a, vec(BC)=b and vec(CD) = c. Then, vec(AE) =`

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The correct Answer is:
A
As in figure, `AB=a,BC=b`,
So, `AD=2b and ED=a`

Now, `AE+ED=AD`
`impliesAE=AD-ED=2b-a`
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