Home
Class 12
MATHS
ABCDE is a pentagon. Forces AB,AE,DC and...

ABCDE is a pentagon. Forces AB,AE,DC and ED act at a point. Which force should be added to this systemm to make the resultant 2AC?

A

AC

B

AD

C

BC

D

BD

Text Solution

Verified by Experts

The correct Answer is:
C
`AE+ED+DC+AB`
`=AD+DC+AB=AC+AB`
Obviously, if BC is added to this system, then it will be
`AC+AB+BC=AC+AC=2AC`.
Promotional Banner

Similar Questions

Explore conceptually related problems

Five points given by A,B,C,D and E are in a plane. Three forces AC,AD and AE act at A and three forces CB,DB and EB act B. then, their resultant is

Force 3N, 4N and 12 N act at a point in mutually perpendicular directions. The magnetitude of the resultant force is :-

Consider the regular hexagon ABCDEF with centre at O (origin). Five forces AB,AC,AD,AE,AF act at the vertex A of a regular hexagon ABCDEF. Then, their resultant is

100 coplanar forces each equal to 10 n act on a body. Each force makes angle pi//50 with the preceding force. What is the resultant of the forces.

There are two forces vector,one of 5N and other of 12N. At what angle should the two vector be added to get the resultant vector of 17N, 7N,and 13N respectively?

The maximum and minimum resultant of two forces acting at a point are 10N and 6N respectively. If each force is increased by 3N, find the resultant of new forces when acting at a paint at an angle of 90^(@) with each-other :-

Two force F_(1)" and "F_(2) are acting on a body. One force is double that of the other force and the resultant is equal to the greater force. Then the angle between the two forces is :-

Three forces of magnitudes 2N, 3N and 6N act at corners of a cube along three sides as shown in figure. Find the resultant of these forces in N.

ABCD is a trapezium with AB||DC . E and F are points on non-parallel sides AD and BC respectively such that EF is parallel to AB (see the figure). Show that (AE)/(ED)=(BF)/(FC)

ABCD is a trapezium with AB||DC . E and F are points on non-parallel sides Ad and BC respectively such that EF is parallel to AB (see the given figure). Show that (AE)/(ED)=(BF)/(FC) .