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If the resultant of three forces F(1)=ph...

If the resultant of three forces `F_(1)=phati+3hatj-hatk,F_(2)=6hati-hatk and F_(3)=-5hati+hatj+2hatk` acting on a particle has a magnitude equal to 5 units, then the value of p is

A

`-6`

B

`-4`

C

`2`

D

4

Text Solution

Verified by Experts

The correct Answer is:
B, C
Let R be the resultant. Then
`R=F_(1)+F_(2)+F_(3)=(p+1)hati+4hatj`
Given, `|R|=5`. Therefore, `(p+1)^(2)+16=25`.
or `p+1=+-3` or `p=2,-4`.
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